2v^2-13v+15=0

Solution for 2v^2-13v+15=0 equation:

2v^2-13v+15=0

a = 2; b = -13; c = +15;
Δ = b2-4ac
Δ = -132-4·2·15
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-7}{2*2}=\frac{6}{4}
=1+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+7}{2*2}=\frac{20}{4}
=5
$